If $P = \frac{x^4 - 8x}{x^3 - x^2 - 2x}, Q = \frac{x^2 + 2x + 1}{x^2 - 4x - 5}$ and $R = \frac{2x^2 + 4x + 8}{x - 5}$, then $(P \times Q) \div R$ is equal to:

$\frac{1}{2}$ 1 2 4

$\frac{1}{2}$