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Physics
Alternating Current
If $I=I_0\sin(ωt-\frac{π}{2})$ and $E = E_0 \sin ωt$, then the AC power consumed is
$P=\frac{E_0I_0}{\sqrt{2}}$
$P=\sqrt{2}E_0I_0$
$P=\frac{E_0I_0}{2}$
$P=0$
The correct answer is Option (4) → $P=0$