If $I=I_0\sin(ωt-\frac{π}{2})$ and $E = E_0 \sin ωt$, then the AC power consumed is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $P=0$
The average power consumed by the circuit is zero because the current and the voltage are out of phase by 90°, meaning that no real power is transferred to the load.