The area enclosed between the curves \(y=\sin x,y=\cos x,0\leq x\leq \frac{\pi}{2}\) is
Answer & explanation
Correct answer: option 3
\(\begin{aligned}\text{Area}&=\int_{0}^{\frac{\pi}{4}}(\cos x-\sin x)dx+\int_{\frac{\pi}{4}}^{\frac{\pi}{2}}(\sin x-\cos x)dx\\ &=2(\sqrt{2}-1)\end{aligned}\)