The average of 21 numbers is 44. The average of first 11 numbers is 48 and that of last 11 numbers is 42. If 11th number is excluded, What is the average of the remaining numbers?

42.9

Sum of 21 numbers = 21 × 44 = 924

Sum of first 11 numbers = 11 × 48 = 528

Sum of last 11 numbers = 11 × 42 = 462

11th number = 924 - ( 528+462)  = 66

After excluding 11th number

New average = \(\frac{858}{20}\) = 42.9