ABC is an isosceles triangle with AC = BC. If \(\angle A=65^\circ\), then what is the measure of \(\angle C\)?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 50°
In an isosceles triangle, the angles opposite the equal sides are equal. The equal sides are AC and BC; the angle opposite BC is \(\angle A\) and the angle opposite AC is \(\angle B\), so these two base angles are equal. The angle sum of a triangle (180°) then gives the third angle.
Base angles, opposite the equal sides: \(\angle B=\angle A=65^\circ\)
Third angle, from the angle sum: \(\angle C=180^\circ-65^\circ-65^\circ=50^\circ\)
