Practicing Success
A hemisphere of radius r is placed in a uniform electric field of strength E. The electric flux through the hemisphere is |
$2 E \pi r^2$ $- E \pi r^2$ $-2 E \pi r^2$ Zero |
$- E \pi r^2$ |
$\phi=\oint E . d S = \oint {}_A^B E . d S + \oint {}_B^x E . d S + \oint {}_x^A E . d S$ $=-E \pi r^2+E \pi r^2-E \pi r^2=-E \pi r^2$ short cut AXB is symmetrical surface ∴ Electric flux due to this part is zero. However, electric flux due to AB part is –EπR2. |