What is the efficiency of an ideal heat engine working between the freezing point and boiling point of water ?
Answer & explanation
Correct answer: option 1
Efficiency of heat engine : \(\eta = (1 - \frac{T_2}{T_1})\)
T2 : Sink Temperature = 0oC = 273 K ;
T1 : Source Temperature = 100oC = 373 K ;
\(\eta = (1 - \frac{273}{373})\)
\(\eta = 26.8%\)