Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Thermodynamics

Question:

What is the efficiency of an ideal heat engine working between the freezing point and boiling point of water ? 

Options:

26.8 %

20 %

12.5 %

6.25 %

Correct Answer:

26.8 %

Explanation:

Efficiency of heat engine : \(\eta = (1 - \frac{T_2}{T_1})\)

T2 : Sink Temperature = 0oC = 273 K ;

T1 : Source Temperature = 100oC = 373 K ;

\(\eta = (1 - \frac{273}{373})\)

\(\eta = 26.8%\)