If dimensions of critical velocity vc of a liquid flowing through a tube are expressed as\( [\eta^x \rho^y r^z] \)where \(\eta\), \(\rho\) and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by :
Answer & explanation
Correct answer: option 2
Critical velocity : \( v_c = \frac{R\eta}{\rho D} \)
⇒ x = 1, y = – 1, z = – 1