What is the equivalent mass of \(H_3PO_4\) in the reaction
\(Ca(OH)_2 + H_3PO_4 \longrightarrow CaHPO_4 + 2H_2O\)
Answer & explanation
Correct answer: option 4
The correct answer is option 4. 49.
As in this reaction only two hydrogen atoms are replaced so its equivalent mass will be given by the following expression:
Equivalent mass of \(H_3PO_4\)
\(= \frac{\text{Molecular mass of }H_3PO_4}{2}\)
\(= \frac{98}{2} = 49\)