Match List I with List II:
| List I | List II |
| (A) Urease | (I) Maltose |
| (B) Maltase | (II) Glucose and fructose |
| (C) Invertase | (III) \(NH_3\) and \(CO_2\) |
| (D) Diastase | (IV) Glucose |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(A) Urease — This matches (III) \( \ce{NH3} \) and \( \ce{CO2} \). Urease hydrolyses urea:
\( \displaystyle \ce{NH2CONH2 + H2O} \xrightarrow{\text{Urease}} \ce{2NH3 + CO2} \)
(B) Maltase — This matches (IV) Glucose. Maltase hydrolyses maltose to two glucose units:
\( \displaystyle \underset{\text{maltose}}{\ce{C12H22O11}} + \ce{H2O} \xrightarrow{\text{Maltase}} \underset{\text{glucose}}{\ce{2C6H12O6}} \)
(C) Invertase — This matches (II) Glucose and fructose. Invertase hydrolyses cane sugar:
\( \displaystyle \underset{\text{cane sugar}}{\ce{C12H22O11}} + \ce{H2O} \xrightarrow{\text{Invertase}} \underset{\text{glucose}}{\ce{C6H12O6}} + \underset{\text{fructose}}{\ce{C6H12O6}} \)
(D) Diastase — This matches (I) Maltose. Diastase breaks starch down to maltose:
\( \displaystyle \underset{\text{starch}}{\ce{2(C6H10O5)_n}} + n\ce{H2O} \xrightarrow{\text{Diastase}} \underset{\text{maltose}}{n\ce{C12H22O11}} \)
NCERT (Pre-rationalised edition, 2022-23):
Enzyme Catalysis – …
