Samir and Puneet can complete the same work in 10 days and 15 days respectively. The work was assigned for ₹4500. After working together for 3 days Samir and Puneet involved Ashok. The work was completed in total 5 days. What amount (in ₹) was paid to Ashok?
Answer & explanation
Correct answer: option 3
Samir = 10 days. Puneet = 15 days,
⇒ Samir + Puneet worked for 3 days = (3 + 2) x 5 = 15 units. .. (Efficiency × Days = Total work)
⇒ Remaining work is completed with the help of Ashok in 5 days;
⇒ \(\frac{15}{3 + 2 + Ashok}\) = 2 days. ..(\(\frac{Work}{Efficiency}\) = Time)
⇒ \(\frac{15}{5 + Ashok}\) = 2
⇒ 15 = 10 + 2(Ashok)
⇒ 2(Ashok) = 5
⇒ Ashok = \(\frac{5}{2}\) = 2.5 (Efficiency)
The amount given for the work is Rs. 4500.
Share of everyone will be = (3 + 2 + 2.5)x = 4500
⇒ 7.5x = 4500
⇒ x = 600.
As, Ashok helped in doing half of the work. Therefore his share will be = \(\frac{600}{2}\) = 300
⇒ 300 x Ashok's efficiency ⇒ 300 x 2.5 = 750
Therefore, Ashok's share will be Rs. 750.