Samir and Puneet can complete the same work in 10 days and 15 days respectively. The work was assigned for ₹4500. After working together for 3 days Samir and Puneet involved Ashok. The work was completed in total 5 days. What amount (in ₹) was paid to Ashok?

750

Samir = 10 days. Puneet = 15 days,

⇒ Samir +  Puneet worked for 3 days = (3 + 2) x 5 = 15 units.    .. (Efficiency × Days = Total work)

⇒ Remaining work is completed with the help of Ashok in 5 days;

⇒ \(\frac{15}{3 + 2 + Ashok}\) = 2 days.               ..(\(\frac{Work}{Efficiency}\) = Time)

⇒ \(\frac{15}{5 + Ashok}\) = 2

⇒ 15 = 10 + 2(Ashok)

⇒ 2(Ashok) = 5

⇒ Ashok = \(\frac{5}{2}\) = 2.5   (Efficiency)

The amount given for the work is Rs. 4500.

Share of everyone will be = (3 + 2 + 2.5)x = 4500

⇒ 7.5x = 4500

⇒ x = 600.

As, Ashok helped in doing half of the work. Therefore his share will be =  \(\frac{600}{2}\) = 300

⇒ 300 x Ashok's efficiency ⇒ 300 x 2.5 = 750 

Therefore, Ashok's share will be Rs. 750.