\(\int \sqrt{1+x^{2}}dx\) is equal to
Answer & explanation
Correct answer: option 1
\(\int \sqrt{x^{2}+a^{2}}dx=\frac{1}{2}x\sqrt{x^{2}+a^{2}}+\frac{a^{2}}{2}\log \left|x+\sqrt{x^{2}+a^{2}}\right|+C\)
\(\int \sqrt{1+x^{2}}dx\) is equal to
Correct answer: option 1
\(\int \sqrt{x^{2}+a^{2}}dx=\frac{1}{2}x\sqrt{x^{2}+a^{2}}+\frac{a^{2}}{2}\log \left|x+\sqrt{x^{2}+a^{2}}\right|+C\)