Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

Let $\left|\begin{array}{rr}3 x & -7 \\ 1 & 4\end{array}\right|=\left|\begin{array}{ll}3 & 2 \\ 4 & x\end{array}\right|$, then value of $x$ is:

Options:

$\frac{-5}{3}$

1

-1

$\frac{2}{7}$

Correct Answer:

$\frac{-5}{3}$

Explanation:

The correct answer is Option (1) - $\frac{-5}{3}$