Find the value of \(\frac{sec45°\;+\;cot45°}{sin30°\;+\;tan45°}\) .
Answer & explanation
Correct answer: option 3
⇒ \(\frac{sec45°\;+\;cot45°}{sin30°\;+\;tan45°}\)
= \(\frac{√2 + 1 }{ \frac{1}{2} + 1 }\) = \(\frac{2√2 + 2 }{3}\)
Find the value of \(\frac{sec45°\;+\;cot45°}{sin30°\;+\;tan45°}\) .
Correct answer: option 3
⇒ \(\frac{sec45°\;+\;cot45°}{sin30°\;+\;tan45°}\)
= \(\frac{√2 + 1 }{ \frac{1}{2} + 1 }\) = \(\frac{2√2 + 2 }{3}\)