Practicing Success
The amount of work done in moving a charge of 4C across two points having a potential difference of 6V is ______. |
48 J 12 J 36 J 24 J |
24 J |
The correct answer is option 4. 24 J. The amount of work done in moving a charge across a potential difference is given by the formula: \[ \text{Work} = \text{Charge} \times \text{Potential difference} \] Given that the charge \( Q = 4 \, \text{C} \) and the potential difference \( V = 6 \, \text{V} \), we can use the formula to find the work done: \[ \text{Work} = Q \times V = 4 \, \text{C} \times 6 \, \text{V} = 24 \, \text{J} \] Therefore, the amount of work done in moving a charge of 4 C across two points having a potential difference of 6 V is \( 24 \, \text{J} \). So, the correct answer is: \( 24 \, \text{J} \) |