The degree of the differential equation $\left(1-\left(\frac{d y}{d x}\right)^2\right)^{3 / 2}=k \frac{d^2 y}{d x^2}$ is:

2

The correct answer is Option (2) → 2

$\left(1-\left(\frac{d y}{d x}\right)^2\right)^{3 / 2}=k \frac{d^2 y}{d x^2}$

$⇒\left[1-\left(\frac{d y}{d x}\right)^2\right]^3=k^2\left(\frac{d^2 y}{d x^2}\right)^2$

so degree = 2