The perimeter of a rectangle is 22 cm and its area is 28 cm2. Find the length of its shorter side (in cm). |
6 7 4 3 |
4 |
Perimeter of rectangle = 2( l + b) ATQ, 2( l + b) = 22 ( l + b ) = 11 Area of rectangle = l × b ATQ, l × b= 28 So, l and b can be 7 & 4 Because , 7 + 4 = 11 & 7 × 4 = 28 So, Length of shorter side = 4 cm The correct answer is Option (3) → 4 |