CUET Preparation Today
At any place on earth, the horizontal component of earth's magnetic field is times the vertical component. The angle of dip at that place will be- |
$60^o$ $45^o$ $90^o$ $30^o$ |
$30^o$ |
$tan \theta = \frac{B_V}{B_H} = \frac{B_V}{\sqrt 3 B_V} = \frac{1}{\sqrt 3}$ $ \theta = 30^o$ |
