Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

The value of $c$ in Lagrange's theorem for the function $f(x)=|x|$ in the interval $[-1,1]$, is

Options:

0

$1 / 2$

$-1 / 2$

non-existent in the interval

Correct Answer:

non-existent in the interval

Explanation:

f(x) is not differentiable at $x=0 \in(-1,1)$.

So, Lagrange's theorem is not applicable. Hence, c does not exist.