CUET Preparation Today
The value of $c$ in Lagrange's theorem for the function $f(x)=|x|$ in the interval $[-1,1]$, is |
0 $1 / 2$ $-1 / 2$ non-existent in the interval |
non-existent in the interval |
f(x) is not differentiable at $x=0 \in(-1,1)$. So, Lagrange's theorem is not applicable. Hence, c does not exist. |
