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If (3 + 2\(\sqrt {5}\))2 = 29 + K\(\sqrt {5}\) Find value of K2 |
12 6 144 24 |
144 |
Formula → (a + b)2 = a2 + b2 + 2ab Given, (3 + 2\(\sqrt {5}\))2 = 29 + K\(\sqrt {5}\) ⇒ 9 + 20 + 12\(\sqrt {5}\) = 29 + K\(\sqrt {5}\) 29 + 12\(\sqrt {5}\) = 29 + K\(\sqrt {5}\) [compare coefficients] K = 12 K2 = 144 |
