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First diffraction minima due to a single slit of width $1.0 × 10^{–5} cm$ is at 30°. Then wavelength of light used is |
400 Å 500 Å 600 Å 700 Å |
500 Å |
As $a\, \sin θ = nλ$ or $λ=\frac{a\, \sin θ}{n}$ or $λ=1.0×10^{-5}×\sin 30°=1.0×10^{-5}×\frac{1}{2}$ $= 0.5 × 10^{–5} = 5 × 10^{–6} cm$ $=500 Å$ |
