Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

General Ability

Topic

Age Problems

Question:

The ratio of the ages of Seeta and Geeta is 2:7. After 6 years, the ratio of their ages will be 1:2. What is the difference in their present ages in years?

 

Options:

8

9

10

11

Correct Answer:

10

Explanation:

According to the question:

\(\frac{\text{2x + 6} }{7x + 6 }\) = \(\frac{1 }{ 2}\)

4x + 12 = 7x + 6

3x = 6

x = 2

Present age of Seeta = 2 x 2 = 4 years

Present age of Geeta = 2 x 7 = 14 years

Difference in the present ages of Seeta and Geeta is 10 years.