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If $|\vec a.\vec b|=|\vec a×\vec b|$, then the angle between $\vec a$ and $\vec b$, is |
0° 180° 150° 45° |
45° |
We have, $|\vec a.\vec b|=|\vec a×\vec b|$ $⇒|\vec a||\vec b||\cos θ|=|\vec a||\vec b|\sin θ$ $⇒|\cos θ|=\sin θ$ $⇒θ=45°,135°$ |
