Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Electro Chemistry

Question:

Match List-I with List-II

List-I Cell

List-II Reaction

(A) Fuel Cell

(I) Anode: $Zn(s) → Zn^{2+} + 2e^-$

Cathode: $MnO_2 + NH^{4+} + e^- → MnO(OH) + NH_3$

(B) A secondary cell

(II) Cathode: $O_2 (g) + 2H_2O(l) + 4e^- → 4OH^- (aq)$

Anode: $2H_2 (g) + 4OH^-(aq) → 4H_2O(l) + 4e^-$

(C) Mercury cells

(III) $Pb(s) + PbO_2 (s) + 2H_2SO_4 (aq) → 2PbSO_4 (s) + 2H_2O(l)$

(D) Leclanche cell (Simplified)

(IV) $Zn(Hg) + HgO(s) → ZnO(s) + Hg(l)$

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Correct Answer:

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Explanation:

The correct answer is Option (2) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Each electrochemical cell has a characteristic overall or electrode reaction:

Fuel cell → Hydrogen–oxygen reaction

Secondary cell → Lead–acid reaction

Mercury cell → Zn–HgO system

Leclanche cell → Zn–MnO₂ system

List-I Cell

List-II Reaction

(A) Fuel Cell

(II) Cathode: $O_2 (g) + 2H_2O(l) + 4e^- → 4OH^- (aq)$

Anode: $2H_2 (g) + 4OH^-(aq) → 4H_2O(l) + 4e^-$

(B) A secondary cell

(III) $Pb(s) + PbO_2 (s) + 2H_2SO_4 (aq) → 2PbSO_4 (s) + 2H_2O(l)$

(C) Mercury cells

(IV) $Zn(Hg) + HgO(s) → ZnO(s) + Hg(l)$

(D) Leclanche cell (Simplified)

(I) Anode: $Zn(s) → Zn^{2+} + 2e^-$

Cathode: $MnO_2 + NH^{4+} + e^- → MnO(OH) + NH_3$