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If 2x + \(\frac{9}{x}\) = 9 What can be the minimum value of x2 + \(\frac{1}{x^2}\) |
\(\frac{36}{95}\) \(\frac{26}{95}\) \(\frac{97}{36}\) \(\frac{95}{362}\) |
\(\frac{97}{36}\) |
Given, 2x + \(\frac{9}{x}\) = 9 2x2 + 9 = 9x 2x2 - 9x + 9 = 0 roots are x = 3 x = \(\frac{3}{2}\) Take, x = \(\frac{3}{2}\) ⇒ x2 + \(\frac{1}{x^2}\) = \(\frac{9}{4}\) + \(\frac{4}{9}\) = \(\frac{97}{36}\) |
