Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Question:

Three varieties A, B and C of rice are mixed together in the ratio 1 : 1 : 3 respectively. The price of rice A is Rs 127 per kg and that of rice B is Rs 135 per kg. If the price of the mixture is Rs. 152 per kg, then the price per kg of rice of type C is:

Options:

Rs. 148

Rs. 156

Rs. 174

Rs. 166

Correct Answer:

Rs. 166

Explanation:

The correct answer is Option (4) → Rs. 166

Given mixture ratio: A : B : C = 1 : 1 : 3

Prices: $P_A = 127$, $P_B = 135$, $P_{mixture} = 152$, $P_C = ?$

Weighted average formula:

$\frac{1*127 + 1*135 + 3*P_C}{1 + 1 + 3} = 152$

Simplify numerator and denominator:

$\frac{127 + 135 + 3P_C}{5} = 152$

$262 + 3P_C = 760$

$3P_C = 760 - 262 = 498$

$P_C = \frac{498}{3} = 166$

Price per kg of rice C = Rs. 166