CUET Preparation Today
A train, 150 m long is running at 90 km/h. How long (in seconds) will it take to clear a platform that is 300 m long? |
6 18 12 50 |
18 |
90km/h = 90 × \(\frac{5 }{18}\) m/sec = 25 m/sec Time = \(\frac{Distance }{Speed}\) = \(\frac{(150+300) }{25}\) = \(\frac{(450) }{25}\) = 18 sec
= \(\frac{(150+300) }{25}\) |
