The area enclosed by the curve \(x=a\cos t,y=a\sin t, t\in [0,2\pi]\) is
Answer & explanation
Correct answer: option 3
\(\begin{aligned}\text{Area}&=\frac{1}{2}\int_{0}^{2\pi}\left(x\frac{dy}{dt}-y\frac{dx}{dt}\right)dt\\ &=\pi a\end{aligned}\)
Correct answer: option 3