CUET Preparation Today
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a b c d |
c |
$\text{Debroglie wavelength }\lambda = \frac{h}{p} = \frac{h}{\sqrt {2mE}} = \frac{h}{\sqrt {2mqV}} $ $\frac{\lambda_A}{\lambda_B} = \sqrt{\frac{m_B}{m_A}} \sqrt{\frac{V_B}{V_A}} = \sqrt{\frac{4m}{m}} \sqrt{\frac{2500}{50}} = 10\sqrt 2 =14.14 $ |
