Figure below shows an electric dipole placed in an electric field. Wh…

The correct answer is Option (2) → Torque $τ=0$, but net force is towards left

$τ$, Torque = $r\,F\sin θ$

Here, $θ=0°$ [Angle between dipole and $\vec E$]

$τ=qdE\sin 0°$

$=0$

Also,

Spacing between electric lines of force decreases from left to right. Therefore, force on +q charge of dipole placed to the right is larger as compared to force on -q.

∴ Dipole will experience force toward the right.