Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Question:

A= HCF of \(\frac{3}{4}\) and \(\frac{9}{16}\) and B= LCM of \(\frac{16}{9}\) and \(\frac{4}{25}\), then the value of A + B will be? 

Options:

\(\frac{259}{16}\)

\(\frac{70}{23}\)

\(\frac{271}{80}\)

\(\frac{260}{71}\)

Correct Answer:

\(\frac{259}{16}\)

Explanation:

\(\frac{3}{4}\), \(\frac{9}{16}\) → HCF = \(\frac{HCF}{LCM}\) = \(\frac{3}{16}\)

\(\frac{16}{9}\), \(\frac{4}{25}\) → LCM = \(\frac{LCM}{HCF}\) = \(\frac{16}{1}\)

Now, \(\frac{3}{16}\) + 16 = \(\frac{259}{16}\)