Find odd one out in the given series.
6, 24, 60, 120, 211, 336
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 211
Each term is \(n^3-n\), a cube minus its own base:
\(2^3-2=6\), \(3^3-3=24\), \(4^3-4=60\), \(5^3-5=120\)
\(6^3-6=210\), but the series prints 211
\(7^3-7=336\)
So 211 is the odd one out; the correct term is 210.