Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) |
(A)-(IV), (B)-(I), (C)-(II), (D)-(III) |
The correct answer is Option (1) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
$\text{(A) } x\,dy - (y + x^2)\,dx = 0$ $\Rightarrow \frac{dy}{dx} = \frac{y + x^2}{x}$ $\text{IF} = e^{\int -\frac{1}{x}\,dx} = \frac{1}{x}$ $\Rightarrow \text{(A)} \rightarrow \text{(IV)}$ $\text{(B) } x\,dy + (2y + x^2)\,dx = 0$ $\Rightarrow \frac{dy}{dx} = -\frac{2y + x^2}{x}$ $\text{IF} = e^{\int \frac{2}{x}\,dx} = x^2$ $\Rightarrow \text{(B)} \rightarrow \text{(I)}$ $\text{(C) } (3y - x^2)\,dx + x\,dy = 0$ $\Rightarrow \frac{dy}{dx} = -\frac{3y - x^2}{x}$ $\text{IF} = e^{\int \frac{3}{x}\,dx} = x^3$ $\Rightarrow \text{(C)} \rightarrow \text{(II)}$ $\text{(D) } (y + 3x^2)\,dx + x\,dy = 0$ $\Rightarrow \frac{dy}{dx} = -\frac{y + 3x^2}{x}$ $\text{IF} = e^{\int \frac{1}{x}\,dx} = x$ $\Rightarrow \text{(D)} \rightarrow \text{(III)}$ |