Phone calls arrive at the rate of 48 per hour at the reservation desk for Indian Airlines. Compute the probability of receiving three calls in a 5 minutes interval of time. |
0.205 0.146 0.192 0.091 |
0.192 |
The correct answer is Option (3) → 0.192 Given number of phone calls arrives per hour is 48. Let random variable X be the number of phone calls in 5 minutes interval of time, then $λ = 48 ×\frac{5}{60}⇒λ=4$. So, $P(X=3)=\frac{4^3e^{-4}}{3}=\frac{64 × 0.018}{6}= 0.192$ |