The area bounded by the \(y-\) axis, \(y=\cos x\) and \(y=\sin x\) when \(0\leq x\leq \frac{\pi}{2}\) is
Answer & explanation
Correct answer: option 2
they intersect at $x=\frac{\pi}{4}$
So required area = $\int\limits_{0}^{\frac{\pi}{4}}\cos x-\sin xdx$
$=\left[\sin x+\cos x\right]_{0}^{\frac{\pi}{4}}=(\sqrt{2}-1)$