b

$\text{The given network of resistor is a balanced wheatstone bridge is } R_{eq} = \frac{2\times4}{2+4} = \frac{4}{3}\Omega=1.3 \Omega$

$\text{Net Resistance is } R = 1.7+ 1.3 = 3.0\Omega$

 $\text{ EMF Induced is }\xi = Blv = 1\times 0.05\times 0.01 = 5\times 10^{-4} V$

$I = \frac{\xi}{R} = \frac{5\times 10^{-4}}{3} = 170 \mu A$