If the perimeter of a certain rectangle is 50 units and its area is 114 sq. units, then how many units is breadth shorter than length ?
Answer & explanation
Correct answer: option 4
Perimeter of rectangle = 2 (l+b)
⇒ 50 = 2(l+b)
⇒ (l+b) = 25
Area of rectangle = l × b
Now,
(l - b)2 = (l + b)2 - 4lb
⇒ (l - b)2 = 252 - (4 × 114) = 625 - 456 = 169
⇒ l - b = \(\sqrt {169}\) = 13