The value of $sin^4θ+cos^4θ+2sin^2θcos^2θ$ is :
Answer & explanation
Correct answer: option 1
$sin^4θ+cos^4θ+2sin^2θcos^2θ$
⇒ ( sin²θ + cos²θ )²
⇒ ( 1 )² { sin²θ + cos²θ = 1 }
⇒ 1
The value of $sin^4θ+cos^4θ+2sin^2θcos^2θ$ is :
Correct answer: option 1
$sin^4θ+cos^4θ+2sin^2θcos^2θ$
⇒ ( sin²θ + cos²θ )²
⇒ ( 1 )² { sin²θ + cos²θ = 1 }
⇒ 1