Two parallel chords are drawn in a circle of diameter 10 m. The length of one chord is 8 m and the distance between the two chords is 6 m. Find the length of the other chord.

8 m

Diameter of circle = 10 m

Radius of circle = 5 m

EB = \(\frac{8}{2}\) = 4 m

By using pythagoras theorem,

OB² = EB² + OE²

5² = 4² + OE²

OE² = 25 - 16 = 9

OE = 3 m

It is given that , EF = 6 m

OF = 6 - OE = 6 - 3 = 3 m

By using pythagoras theorem,

OD² = FD² + OF²

5² = FD² + 3²

FD² = 25 - 9 = 16

FD = 4 m

So, CD = 2 × 4 = 8 m

Length of other chord = 8 m