Two parallel chords are drawn in a circle of diameter 10 m. The length of one chord is 8 m and the distance between the two chords is 6 m. Find the length of the other chord.
Answer & explanation
Correct answer: option 4
Diameter of circle = 10 m
Radius of circle = 5 m
EB = \(\frac{8}{2}\) = 4 m
By using pythagoras theorem,
OB² = EB² + OE²
5² = 4² + OE²
OE² = 25 - 16 = 9
OE = 3 m
It is given that , EF = 6 m
OF = 6 - OE = 6 - 3 = 3 m
By using pythagoras theorem,
OD² = FD² + OF²
5² = FD² + 3²
FD² = 25 - 9 = 16
FD = 4 m
So, CD = 2 × 4 = 8 m
Length of other chord = 8 m