The square matrix $A =[a_{ij}]$ given by $a_{ij} = (i-j)^3$, is a
Answer & explanation
Correct answer: option 2
We have,
$a_{ij} = (i-j)^3⇒a_{ij} =(j-i)^3=-(i-j)^3=-a_{ij}$ for all i, j
∴ A is a skew-symmetric matrix.
The square matrix $A =[a_{ij}]$ given by $a_{ij} = (i-j)^3$, is a
Correct answer: option 2
We have,
$a_{ij} = (i-j)^3⇒a_{ij} =(j-i)^3=-(i-j)^3=-a_{ij}$ for all i, j
∴ A is a skew-symmetric matrix.