A particle of mass m and charge q is placed at rest in a uniform electric field E and then released. The kinetic energy attained by the particle after moving a distance y is:

$qEy$

The correct answer is Option (3) → $qEy$

Mass of changed particle = m

Charge on particle = +q

Now,

force (F) on charge particle = qE

and,

Work done by charge particle on moving y distance = kinetic energy

$= qEy$ [$W_0$ force displacement]