When the number of turns of a solenoid is doubled, its self inductance becomes: |
2 times 6 times 8 times 4 times |
4 times |
The correct answer is Option (4) → 4 times The self inductance (L) is, $L=μ_0\frac{N^2A}{l}$ if the number of turns N is doubled: $L'=\frac{μ_0(2N)^2A}{l}=4\frac{μ_0N^2A}{l}$ $L'=4L$ |