Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Find the mean proportion of \(\frac{1}{25}\) and \(\frac{1}{49}\) .

Options:

\(\frac{1}{35}\)

\(\frac{1}{49}\)

\(\frac{1}{5}\)

\(\frac{1}{27}\)

Correct Answer:

\(\frac{1}{35}\)

Explanation:

Mean proportion of a and b = \(\sqrt {a × b }\)

⇒ Mean proportion = \(\sqrt {\frac{1}{25} × \frac{1}{49}}\)

                               = \(\frac{1}{5 × 7}\)  = \(\frac{1}{35}\)