Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Question:

500 g of jaggery syrup has 30% jaggery in it. The quantity of jaggery that should be added to make it 50% of syrup is:

Options:

200 g

750 g

500 g

250 g

Correct Answer:

200 g

Explanation:

The correct answer is Option (1) → 200 g

Given:

Total syrup = 500 g

Jaggery content = 30% ⇒ 0.3 × 500 = 150 g

Let x g of jaggery be added to make jaggery 50% of syrup.

Total syrup after addition = 500 + x

Total jaggery after addition = 150 + x

Required concentration: 50%

$\frac{150 + x}{500 + x} = 0.5$

$150 + x = 0.5(500 + x) = 250 + 0.5x$

$0.5x = 100 ⇒ x = 200 g$