Three of the following four letter groups are alike in a certain way and one is different. Choose the odd one out.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → SVZ
Write each letter’s place in the alphabet (A = 1, B = 2, …, Z = 26) and find the jumps from one letter to the next.
Option (1) SVY — S (19), V (22), Y (25): jumps +3, +3.
Option (2) MPS — M (13), P (16), S (19): jumps +3, +3.
Option (3) SVZ — S (19), V (22), Z (26): jumps +3, +4.
Option (4) KNQ — K (11), N (14), Q (17): jumps +3, +3.
Three groups go +3, +3; SVZ goes +3, +4, so SVZ is the odd one out.