Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

The maximum value of $\sin (\cos x)$ is equal to

Options:

$\sin 1$

1

$\sin(\frac{1}{\sqrt{2}})$

$\sin(\frac{\sqrt{3}}{2})$

Correct Answer:

$\sin 1$

Explanation:

$\cos x ∈ [−1, 1] ∀\, x ∈ R$ and sin x is increasing in $\left[-\frac{π}{2},\frac{π}{2}\right]$

⇒ Maximum of $\sin (\cos x) = \sin 1$