Practicing Success
The maximum value of $\sin (\cos x)$ is equal to |
$\sin 1$ 1 $\sin(\frac{1}{\sqrt{2}})$ $\sin(\frac{\sqrt{3}}{2})$ |
$\sin 1$ |
$\cos x ∈ [−1, 1] ∀\, x ∈ R$ and sin x is increasing in $\left[-\frac{π}{2},\frac{π}{2}\right]$ ⇒ Maximum of $\sin (\cos x) = \sin 1$ |