A number between 1000 & 2000 which w

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Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Question:

A number between 1000 & 2000 which when divided by 30, 36 & 80 gives a remainder 11 in each case is:

Options:

1523

1712

1451

1641

Correct Answer:

1451

Explanation:

Number will be divisible by 30, 36 and 80 gives remainder 11 each

Therefore,

LCM of 30, 36, 80 = 720

Let number will be 720 × k + 11

Put, k = 2

Then the number = 720 × 2 + 11

⇒ 1440 + 11

∴ The number is 1451