A number between 1000 & 2000 which when divided by 30, 36 & 80 gives a remainder 11 in each case is:
Answer & explanation
Correct answer: option 3
Number will be divisible by 30, 36 and 80 gives remainder 11 each
Therefore,
LCM of 30, 36, 80 = 720
Let number will be 720 × k + 11
Put, k = 2
Then the number = 720 × 2 + 11
⇒ 1440 + 11
∴ The number is 1451