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Maximum value of $\log x/x$ in interval $[2 , ∞]$ is |
$\log 2/2$ 0 $1/e$ 1 |
$1/e$ |
The correct answer is Option (3) → $1/e$ $f'(x)=\frac{1}{x^2}(1-\ln x)$ Clearly f(x) increasing for x < e and decreases for x > e ⇒ x = e is the point of local maxima ∴ maximum f(x) = $\frac{1}{e}$ Hence (3) is the correct answer. |
