The value of \(\int\frac{1}{3x}dx\)1\[\frac{1}{3}log 3x + c\]2\[\frac{-1}{3}log 3x + c\]3\[\frac{1}{3}log x + c\]4\[\frac{-1}{3}log 3x + c\]Answer & explanation+Correct answer: option 3\(\int\frac{1}{x}dx\) = log x + c
