If $f, g : R \to R$ be defined by $f(x) = 2x + 1$ and $g(x) = x^2 - 2, \forall x \in R,$ respectively. Then, find $gof$.

$4x^2 + 4x - 1$

The correct answer is Option (3) → $4x^2 + 4x - 1$ ##

Given that, $f(x) = 2x + 1$ and $g(x) = x^2 - 2, \forall x \in R$

$∴g of = g \{f(x)\}$

$= g(2x + 1) = (2x + 1)^2 - 2$

$= 4x^2 + 4x + 1 - 2$

$= 4x^2 + 4x - 1$