If $f, g : R \to R$ be defined by $f(x) = 2x + 1$ and $g(x) = x^2 - 2, \forall x \in R,$ respectively. Then, find $gof$.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $4x^2 + 4x - 1$ ##
Given that, $f(x) = 2x + 1$ and $g(x) = x^2 - 2, \forall x \in R$
$∴g of = g \{f(x)\}$
$= g(2x + 1) = (2x + 1)^2 - 2$
$= 4x^2 + 4x + 1 - 2$
$= 4x^2 + 4x - 1$